Calculation of the amount of air that must enter the room in Fire Pump with Diesel Engines

Calculation of the amount of air that must enter the room in Fire Pump with Diesel Engines

For the Radiator Type Fire Pump Engines the below data is required:
1.Amount of air required for the combustion chamber m³/min
2.Heat transferred by the engine to the environment through radiation in kW
3.Engine cooling fan air flow rate m³/min
4.The maximum temperature increase allowed in the room is ΔT ̊C. We can always accept the maximum temperature increase allowed in the room as 10 ̊C. The amount of air required to cool the heat transferred to the environment by the engine through radiation is found from the formula V (m³/min) = H (kW) / 1.099 * 0.017 * ΔT. The resulting value is compared with the engine cooling fan air flow rate, whichever is greater is selected. Because the aim is to make sure the air that will enter is sufficient for the worst conditions. This value is added with the amount of air required for the combustion chamber to find the total amount of air that needs to enter the room.
For example; we will demonstrate for the Clarke JU6R-NLKA33 diesel engine 132 kW @3000 rpm 1.Amount of air required for the combustion chamber m³/min 17.1 m³/min
2.Heat transferred by the engine to the environment through radiation kW 14.8 kW
3.Engine cooling fan air flow rate m³/min 421 m³/min
4.Maximum temperature increase allowed in the room ΔT ̊C 10 ̊C
V = 14.8 / 1.099 *0.017 * 10 = 79.56 m³/min
Engine cooling fan air flow rate m³/min 421 m³/min > 79.56 m³/min
Total amount of air that needs to enter the room = 421 m³/min + 17.1 m³/min = 438.1 m³/min
For the Heat Exchanger Type Fire Pump Engines;
The difference in this application is that there is no radiator hence no cooling fan. As in the radiator application, the amount of air required to cool the heat transferred to the environment by the engine through radiation is first determined and the total amount of air that needs to enter the room is calculated by adding it with the amount of air required for the combustion chamber.
For example ; we will demonstrate for the Clarke JU6H-NL54 diesel engine 177.5 kW @ 3000 rpm
1.Amount of air required for the combustion chamber m³/min 18.3 m³/min
2.Heat transferred to the environment by the engine through radiation kW 16.7 kW
3.Maximum temperature increase allowed in the room ΔT ̊C 10 ̊C
V = 16.7 / 1.099 *0.017 * 10 = 89.78 m³/min
Total amount of air that needs to enter the room = 89.78 m³/min + 18.3 m³/min = 108.08 m³/min